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6k^2+30k=-24
We move all terms to the left:
6k^2+30k-(-24)=0
We add all the numbers together, and all the variables
6k^2+30k+24=0
a = 6; b = 30; c = +24;
Δ = b2-4ac
Δ = 302-4·6·24
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-18}{2*6}=\frac{-48}{12} =-4 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+18}{2*6}=\frac{-12}{12} =-1 $
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